This extends Rbyd.fetch to accept another rbyd, in which case we inherit
the RAM-backed block without rereading it from disk. This avoids an
issue where shrubs can become corrupted if the disk is being
simultaneously written and debugged.
Normally we can detect the checksum mismatch and toss out the rbyd
during fetch, but shrub pointers don't include a checksum since they
assume the containing rbyd has already been checksummed.
It's interesting to note this even avoids the memory copy thanks to
Python's reference counting.
Christopher Haster
a0ab7bda26